[Python][DFS]단지번호 붙이기 

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direction = ((-1,0), (1,0), (0,-1), (0,1))

def bfs(y, x, num):
    global n
    check[y][x] = num
    queue = [(y,x)]
    cnt = 1
    while queue:
        curr_y, curr_x = queue.pop(0)
        for d in direction:
            next_y = curr_y + d[0]
            next_x = curr_x + d[1]
            if 0<=next_y<n and 0<=next_x<n:
                if MAP[next_y][next_x] == 1 and check[next_y][next_x]==0:
                    check[next_y][next_x] = num
                    queue.append((next_y, next_x))
                    cnt += 1
    return cnt

n = int(input())
MAP = [list(map(int, input())) for _ in range(n)]
check = [[0]*n for _ in range(n)]

number = 0
result = []

for i in range(n):
    for j in range(n):
        if not check[i][j] and MAP[i][j] != 0:
            number += 1
            c = bfs(i,j,number)
            result.append(c)

print(number)
result.sort()
for i in result:
    print(i)

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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 direction = (( - 1 , 0 ), ( 1 , 0 ), ( 0 , - 1 ), ( 0 , 1 )) def sol (st_y, st_x): global w, h cnt = 0 for d in direction: next_y = st_y + d[ 0 ] next_x = st_x + d[ 1 ] if next_y < 0 or next_y >= h or next_x < 0 or next_x >= w or MAP[next_y][next_x] == 0 : cnt += 1 return cnt while True: w, h = map(int, input() . split()) if (w, h) == ( 0 , 0 ): break MAP = [list(map(int, input() . split())) for _ in range(h)] answer = 0 for i in range(h): for j in range(w): if MAP[i][j] == 0 : continue answer += sol(i,j) print (answer) 아이디어는 단순하다. 모든 좌표를 순회하면서 주변이 땅으로 연결되지 않을때 cnt를 하나씩 증가시킨다.
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