1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 def backtrack (a, k, input): global MAXCANDIDATES c = [ 0 ] * MAXCANDIDATES if k == input: process_solution(a,k) #답이면 원하는 작업한다. else : k += 1 ncandidates = construct_candidates(a,k,input,c) for i in range(ncandidates): a[k] = c[i] backtrack(a, k, input) def process_solution (a, k): print ( "(" , end = "" ) for i in range(k + 1 ): if a[i]: print (i, end = " " ) print ( ")" ) #후보군 구하는 함수 def construct_candidates (a, k, input, c): c[ 0 ] = True c[ 1 ] = False return 2 #Main MAXCANDIDATES = 100 NMAX = 100 a = [ 0 ] * NMAX backtrack(a, 0 , 3 )
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